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Class 10 RD Sharma Solutions - Chapter 11 Constructions - Exercise 11.2 | Set 2
Last Updated: 23 July 2025
In Chapter 11 of Class 10 RD Sharma, we delve into the topic of "Constructions" where students learn the practical aspects of geometry by drawing various geometric figures...
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Class 10 RD Sharma Solutions - Chapter 11 Constructions - Exercise 11.2 | Set 1
Last Updated: 10 February 2023
Question 1. Construct a triangle of sides 4 cm, 5 cm, and 6 cm and then a triangle similar to it whose sides are (2/3) of the corresponding sides of it.Solution:Follow the...
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Class 10 RD Sharma Mathematics Solutions - Chapter 4 Triangles - Exercise 4.6 | Set 2
Last Updated: 23 July 2025
Chapter 4 of RD Sharma's Class 10 mathematics book focuses on "Triangles" which is a fundamental concept in the geometry. This chapter deals with the various properties an...
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Class 10 RD Sharma Solutions - Chapter 2 Polynomials - Exercise 2.3
Last Updated: 23 July 2025
Chapter 2 of RD Sharma's Class 10 Mathematics book delves into the polynomials a fundamental algebraic concept. This chapter introduces polynomials, their types and their ...
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Class 10 RD Sharma Solutions - Chapter 4 Triangles - Exercise 4.6 | Set 1
Last Updated: 23 July 2025
This exercise contains questions regarding the similarity of triangles. Questions in this exercise are based on the concepts of properties of two similar triangles. The RD...
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Class 10 RD Sharma Solutions - Chapter 14 Coordinate Geometry - Exercise 14.3 | Set 3
Last Updated: 25 October 2024
Exercise 14.3 Set 3 of RD Sharma Class 10 Mathematics further expands upon the principles of Coordinate Geometry, focusing on advanced applications of area calculations in...
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Class 10 RD Sharma Solutions - Chapter 14 Coordinate Geometry - Exercise 14.3 | Set 2
Last Updated: 23 July 2025
The Coordinate Geometry is a crucial chapter in Class 10 Mathematics offering a blend of algebra and geometry. It provides students with the tools to analyze geometric sha...
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Class 10 RD Sharma Solutions - Chapter 14 Coordinate Geometry - Exercise 14.5 | Set 3
Last Updated: 23 July 2025
Coordinate Geometry, also known as Analytic Geometry, is a branch of the mathematics that studies geometric properties and spatial relations using coordinate systems. This...
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Class 10 RD Sharma Solutions - Chapter 14 Coordinate Geometry - Exercise 14.3 | Set 1
Last Updated: 25 October 2024
Chapter 14 of RD Sharma Class 10 Mathematics delves into the fascinating world of Coordinate Geometry, with Exercise 14.3 specifically focusing on the concepts of area of ...
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Class 10 RD Sharma Solutions - Chapter 14 Coordinate Geometry - Exercise 14.5 | Set 2
Last Updated: 16 May 2021
Question 12. Prove that the points (a, b), (a1, b1) and (a – a1, b – b1) are collinear if ab1 = a1b.Solution:As we know that 3 points are collinear is the area of the tria...
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Class 10 RD Sharma Solutions - Chapter 11 Constructions - Exercise 11.1
Last Updated: 16 May 2021
Question 1. Determine a point that divides a line segment of length 12 cm internally in the ratio 2 : 3. Also, justify your construction.Solution:Steps of construction:Ste...
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Class 10 RD Sharma Solutions - Chapter 8 Quadratic Equations - Exercise 8.6 | Set 2
Last Updated: 16 May 2021
Question 11. If – 5 is a root of the quadratic equation 2x² + px – 15 = 0 and the quadratic equation p(x² + x) + k = 0 has equal-roots, find the value of k.Solution:2x² + ...
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Class 10 RD Sharma Solutions - Chapter 14 Coordinate Geometry - Exercise 14.5 | Set 1
Last Updated: 16 May 2021
Question 1. Find the area of a triangle whose vertices are:(i) (6, 3), (-3, 5) and (4, -2)Solution:Let us assume ABC is a triangle whose vertices are A(6, 3), B(-3, 5) and...
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Class 10 RD Sharma Solutions - Chapter 8 Quadratic Equations - Exercise 8.6 | Set 1
Last Updated: 16 May 2021
Question 1. Determine the nature of the roots of following quadratic equations :(i) 2x² – 3x + 5 = 0(ii) 2x² – 6x + 3 = 0(iii) 3/5 x² – 2/3 x + 1 = 0(iv) 3x² – 4√3 x + 4 =...
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Class 10 RD Sharma Solutions - Chapter 6 Trigonometric Identities - Exercise 6.1 | Set 1
Last Updated: 30 April 2021
Prove the following trigonometric identities:Question 1. (1 – cos2 A) cosec2 A = 1Solution:We have,L.H.S. = (1 – cos2 A) cosec2 ABy using the identity, sin2 A + cos2 A = 1...
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