Python | Sympy Plane.projection_line() method

In Sympy, the function Plane.projection_line() is used to project the given line onto the given plane through the normal plane containing the line.

Syntax: Plane.projection_line(line)

Parameters:
 line: LinearEntity or LinearEntity3D

Returns: Point3D, Line3D, Ray3D or Segment3D

Example #1:

Python3 1==

# import sympy and Plane, Line, Line3D, Point, Point3D
from sympy import Plane, Line, Line3D, Point, Point3D

p = Line(Point(1, 2), Point(2, 3))

# using Plane()
p1 = Plane(Point3D(1, 2, 3), normal_vector =(1, 0, 1))

# using projection_line()
projectionLine = p1.projection_line(p)

print(projectionLine)

Output:

Line3D(Point3D(5/2, 2, 3/2), Point3D(3, 3, 1))

Example #2:

Python3 1==

# import sympy and Plane, Line, Line3D, Point, Point3D
from sympy import Plane, Line, Line3D, Point, Point3D

p = Line3D(Point3D(1, 2, 3), Point(0, 0, 0))

# using Plane()
p2 = Plane(Point3D(1, 1, 1), normal_vector =(0, 0, 0))

# using projection_line()
projectionLine = p2.projection_line(p)

print(projectionLine)

Output:

Line3D(Point3D(1, 2, 3), Point3D(2, 0, 2))

Python | Sympy Plane.projection_line() method

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