Simplified value of 3x2(2xy - 3xy2 + 4x2y3) is x3y − 9x3y2 + 12x4y3 the detailed solution for the same is added below:
Simplify 3x2(2xy - 3xy2 + 4x2y3)
Solution:
Given,
- 3x2(2xy − 3xy2 + 4x2y3)
Using distributive property and law of exponent {am. an = am+n}
We have:
= 6x2+1y − 9x2+1y2 + 12x2+2y3
= 6x3y − 9x3y2 + 12x4y3
Also Read:
Similar Questions
Question 1. Simplify:
Solution:
Multiply the terms in the numerator, using the multiplication law of exponents.
\frac{4ab^2(-5ab^3)}{10a^2b^2} = \frac{-20(a)^{1+1}(b)^{2+3}}{10a^2b^2} =
\frac{-2a^2b^5}{a^2b^2} Now apply the division law of exponents to evaluate.
= -2a2-2b5-2
= -2a0b3
= -2b3
Question 2. Simplify:
Solution:
Using the property (pm)n = pmn, we have:
\dfrac{(p^{1/7})^{49}}{\left(\dfrac{14p^{1/2}}{(p^{26})^{-1/7}}\right)}=\dfrac{p^{49/7}}{\left(\dfrac{14p^{1/2}}{p^{-26/7}}\right)} Apply the property am/an = am-n in the denominator.
=
\dfrac{p^7}{{14p^{1/2-(-26/7)}}} =
\dfrac{p^7}{{14p^{59/14}}} Again applying the quotient law of exponents, we have:
=
\frac{{p^{7-\frac{59}{14}}}}{14} =
\frac{p^{\frac{39}{14}}}{14}
Question 3. Simplify: [25 × t-4]/[5-3 × 10 × t-8].
Solution:
[25 x t-4]/[5-3 x 10 x t-8] = (52 × t−4)/(5−3 × 5 × 2 × t−8 )
= (52 × t−4)/(5−3+1 × 2 × t−8) [Since, am × an = am+n]
= (52 × t−4)/(5−2 × 2 × t−8)
= (52−(−2) × t−4−(−8))/2 [Since, am/an = am−n]
= (54 × t−4 + 8)/2
= (625/2)(t4)
Question 4. Simplify: 3x2/10x5.
Solution:
Using the property am/ an = am-n, which is known as the quotient law,
3x2/10x5 =
\frac{3x^{2-5}}{10} = 3x-3/ 10
Using the property a-m = 1/ am, which is known as the Negative exponent law,
3x-3/ 10 =
\frac{3}{10x^{3}}
Question 5. Simplify: 12x9/5x60.
Solution:
Using the property am/ an = am - n, which is known as the quotient law,
12x9/ 5x60 =
\frac{12x^{9-60}}{5} = 12x-51/ 5
Using the property a-m = 1/am, which is known as the Negative exponent law,
12x-51/ 5 =
\frac{12}{5x^{51}} .