A perpendicular bisector is a line that intersects a line segment at its midpoint, divides it into two equal parts, and forms a right angle (90°) with it at the point of intersection.
In the figure shown below, the perpendicular bisector divides the line segment AB into two halves at its midpoint.
Properties
A perpendicular bisector divides a line segment into two equal parts at its midpoint.
It intersects the line segment at a right angle (90°).
Every point on the perpendicular bisector is equidistant from the endpoints of the segment.
It passes precisely through the midpoint of the line segment.
For a given line segment, there exists a unique perpendicular bisector.
Construction of a Perpendicular Bisector
A perpendicular bisector of a line segment can be constructed using a ruler and a compass. It divides the given line segment into two equal parts at its midpoint and forms a right angle (90°) with it.
Steps to Construct a Perpendicular Bisector
Draw a line segment XY of any suitable length.
With X as the centre and a radius more than half of XY, draw arcs above and below the line segment.
With Y as the centre and the same radius, draw arcs to intersect the previous arcs.
Mark the points of intersection as P and Q.
Join P and Q. This line PQ is the perpendicular bisector of XY. It intersects XY at point O, which is the midpoint.
Equation for a Perpendicular Bisector
To find the equation of a perpendicular bisector of a line segment:
Find the midpoint of the given line segment.
Determine the slope of the line segment.
Find the negative reciprocal of this slope (this is the slope of the perpendicular bisector).
Use the point-slope form: y - y1 = m(x - x1) to write the equation using the midpoint.
A perpendicular bisector of a triangle is a line that divides a side into two equal parts at its midpoint and is perpendicular (90°) to it. Each triangle has three such bisectors, one for each side. These bisectors intersect at a single point called the circumcenter, which is equidistant from all three vertices and acts as the centre of the circumcircle.
Steps of Construction
Draw a triangle and label the vertices as A, B, and C.
With B as the centre and a radius greater than half of BC, draw arcs above and below the side BC.
With C as the centre and the same radius, draw arcs intersecting the previous arcs.
Mark the points of intersection as X and Y, and join them to form the perpendicular bisector of BC.
Repeat the same process for sides AB and AC.
The three perpendicular bisectors intersect at a point called the circumcenter.
Perpendicular Bisector Theorem
The perpendicular bisector theorem states that any point lying on the perpendicular bisector of a line segment is equidistant from its endpoints.
In the above figure, points Q, R, S, and T lie on the perpendicular bisector of line segment MN. Therefore:
MQ = NQ
MR = NR
MS = NS
MT = NT
This shows that every point on the perpendicular bisector is at an equal distance from both endpoints.