NCERT Solutions Class 8 – Chapter 2 Linear Equations in One Variable – Exercise 2.2

Last Updated : 19 Apr, 2024

Solve the following linear equations.

Question 1. x/2 - 1/5 = x/3 + 1/4

Solution:

(5x - 2)/10 = (4x + 3)/12   ...(Taking LCM on both the sides)

12(5x - 2) = 10 (4x + 3)  ...(Cross multiplying)

60x - 24 = 40x + 30   ...(Solving the brackets)

60x - 40x = 30 + 24  ...(Transposing terms of x to LHS and others to RHS)

20x = 54

x = 54/20 or 27/10 ... (Solution)

Verification:

Putting value of "x" in the equation to check if our answer is correct

27/20 - 1/5 = 27/30 + 1/4

(27 - 4)/20 = (108 + 30)/120

23/20 = 138/120

23/20 = 23/20

LHS = RHS (Hence Proved that solution is correct)

Question 2. n/2 - 3n/4 + 5n/6 = 21

Solution:

(6n - 9n + 10n)/12 = 21   ...(Taking LCM and solving LHS)

7n/12 = 21 (Solving LHS)

7n = 21 × 12

n = 36  ...(Solution)

Verification:

Putting value of "n" in the equation to check if our answer is correct

36/2 - 108/4 + 180/6 = 21

18 - 27 + 30 = 21

21 = 21

LHS = RHS (Hence Proved that solution is correct)

Question 3. x + 7 - 8x/3 = 17/6 - 5x/2

Solution:

x - 8x/3 + 5x/2 = 17/6 - 7  ...(Transposing terms of x to LHS and others to RHS)

(6x - 16x + 15x)/6 = (17 - 42)/6  ...(Taking LCM and solving)

5x/6 = -25/6

x = -5  ...(Solution)

Verification -

Putting value of "x" in the equation to check if our answer is correct

-5 + 7 - (-40)/3 = 17/6 - (-25)/2

2 + 40/3 = 17/6 + 25/2

46/3 = (17 + 75)/6

46/3 = 92/6

46/3 = 46/3

LHS = RHS  (Hence Proved that solution is correct)

Question 4. (x - 5)/3 = (x - 3)/5

Solution:

5(x - 5) = 3(x - 3)  ...(Cross multiply)

5x - 25 = 3x - 9

2x = 16

x = 8  ...(Solution)

Verification -

Putting value of "x" in the equation to check if our answer is correct

(8 - 5)/3 = (8 - 3)/5

3/3 = 5/5

1 = 1

LHS = RHS (Hence Proved that solution is correct)

Question 5. (3t - 2)/4 - (2t + 3)/3 = 2/3 - t

Solution:

3t/4 - 1/2 - 2t/3 -1 = 2/3 - t  ...(Solving brackets)

3t/4 - 2t/3 + t = 2/3 + 1 + 1/2  ...(Transposing terms of x to LHS and others to RHS)

(9t - 8t + 12t)/12 = (4 + 6 + 3)/6  ...(Taking LCM both sides)

13t/12 = 13/6

t = 2   ...(Solution)

Verification -

Putting value of "t" in the equation to check if our answer is correct

(3 × 2 - 2)/4 - (2 × 2 + 3)/3 = 2/3 - 2

4/4 - 7/3 = 2/3 - 2

(12 - 28)/12 = (2 - 6)/3

-16/12 = -4/3

-4/3 = -4/3

LHS = RHS (Hence Proved that solution is correct)

Question 6. m - (m - 1)/2 = 1 - (m - 2)/3

Solution:

(2m - m + 1)/2 = (3 - m + 2)/3  ...(Taking LCM both sides)

(m + 1)/2 = (5 - m)/3

3(m + 1) = 2(5 - m)  ...(Cross multiplying)

3m + 3 = 10 - 2m

5m = 7

m = 7/5  ...(Solution)

Verification -

Putting value of "m" in the equation to check if our answer is correct

7/5 - (7/5 - 1)/2 = 1 - (7/5 - 2)/3

7/5 - 1/5 = 1 - (-3)/15

6/5 = 1 + 1/5

6/5 = 6/5

LHS = RHS (Hence Proved that solution is correct)

Question 7. 3(t - 3) = 5(2t + 1)

Solution:

3t - 9 = 10t + 5  ...(Opening brackets)

3t - 10t = 9 + 5

-7t = 14

t = -2  ...(Solution)

Verification -

Putting value of "t" in the equation to check if our answer is correct

3(-2 - 3) = 5(2(-2) + 1)

3(-5) = 5(-4 +1)

-15 = -15

LHS = RHS (Hence Proved that solution is correct)

Question 8. 15(y – 4) – 2(y – 9) + 5(y + 6) = 0

Solution:

15y - 60 - 2y + 18 + 5y + 30 = 0

18y - 12 = 0

y = 12/18 or 2/3  ...(Solution)

Verification -

Putting value of "y" in the equation to check if our answer is correct

15(2/3 - 4) - 2(2/3 - 9) + 5(2/3 + 6) = 0

10 - 60 - 4/3 +18 + 10/3 + 30 = 0

-50 -4/3 + 48 + 10/3 = 0

-2 + 6/3 = 0

-2 + 2 = 0

0 = 0

LHS = RHS (Hence Proved that solution is correct)

Question 9. 3(5z – 7) – 2(9z – 11) = 4(8z – 13) – 17

Solution:

15z - 21 - 18z + 22 = 32z - 52 - 17  ...(Solving the brackets)

-3z + 1 = 32z - 69

-35z = -70

z = 2  ...(Solution)

Verification -

Putting value of "z" in the equation to check if our answer is correct

3(5(2) - 7) - 2(9(2) - 11) = 4(8(2) - 13) - 17

3(3) - 2(7) = 4(3) - 17

9 - 14 = 12 - 17

-5 = -5

LHS = RHS (Hence Proved that solution is correct)

Question 10. 0.25(4f – 3) = 0.05(10f – 9)

Solution:

f - 0.25(3) = 0.5f - 0.05(9)

f - 0.75 = 0.5f - 0.45

0.5f = 0.75 - 0.45

f = 3/5 or 0.6 (Solution)

Verification -

Putting value of "f" in the equation to check if our answer is correct

0.25(4(0.6) - 3) = 0.05(10(0.6) - 9)

0.25(2.4 - 3) = 0.05(6 - 9)

0.25 × (-0.6) = 0.05 × (-3)

-0.15 = -0.15

LHS = RHS (Hence Proved that solution is correct)

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