TCS Coding Practice Question | Sum of Digits of a number

Given a number, the task is to find the Sum of Digits of this number using Command Line Arguments.

Examples:

Input: num = 687
Output: 21

Input: num = 12
Output: 3

Approach:

Since the number is entered as Command line Argument, there is no need for a dedicated input line
Extract the input number from the command line argument
This extracted number will be in string type.
Convert this number into integer type and store it in a variable, say num
Declare a variable to store the sum and set it to 0
Repeat the next two steps till the number is not 0
Get the rightmost digit of the number with help of remainder '%' operator by dividing it with 10 and add it to sum.
Divide the number by 10 with help of '/' operator
Print or return the sum

Program:

// C program to find
// the sum of digits of a number
// using command line arguments

#include <stdio.h>
#include <stdlib.h> /* atoi */

// Function to Find the sum of digits
int findSumOfDigits(int num)
{

    // Variable to store the
    // the sum of digits
    int sum = 0;

    // Traverse through the number digit by digit
    while (num > 0) {

        // Add the last digit of num
        // to the sum
        sum = sum + (num % 10);

        // Remove the last digit from the num
        num = num / 10;
    }

    // Return the sum
    return sum;
}

// Driver code
int main(int argc, char* argv[])
{

    int num;

    // Check if the length of args array is 1
    if (argc == 1)
        printf("No command line arguments found.\n");
    else {

        // Get the command line argument and
        // Convert it from string type to integer type
        // using function "atoi( argument)"
        num = atoi(argv[1]);

        // Find the sum of digits and print it
        printf("%d\n", findSumOfDigits(num));
    }
    return 0;
}

Java

// Java program to find
// the sum of digits of a number
// using command line arguments

class GFG {

    // Function to Find the sum of digits
    public static int findSumOfDigits(int num)
    {

        // Variable to store the
        // the sum of digits
        int sum = 0;

        // Traverse through the number digit by digit
        while (num > 0) {

            // Add the last digit of num
            // to the sum
            sum = sum + (num % 10);

            // Remove the last digit from the num
            num = num / 10;
        }

        // Return the sum
        return sum;
    }

    // Driver code
    public static void main(String[] args)
    {

        // Check if length of args array is
        // greater than 0
        if (args.length > 0) {

            // Get the command line argument and
            // Convert it from string type to integer type
            int n = Integer.parseInt(args[0]);

            // Find the sum of digits and print it
            System.out.println(findSumOfDigits(n));
        }
        else
            System.out.println("No command line "
                               + "arguments found.");
    }
}

Python

# Python program to find the sum of digits of a number

def findSumOfDigits(num):
      sum = 0
      # Traverse through the number digit by digit
      while (num > 0):
            # Add the last digit of num to the sum
            sum = sum + (num % 10)
            # Remove the last digit from the num
            num = num // 10
      return sum

# take the input 
num=(input())
# convert into integer type
n=int(num)
# check the length of number
if len(num)>0:
        print(findSumOfDigits(n))
else:
       print("No command line")

C++

#include <iostream>
#include <cstdlib> // for atoi function
using namespace std;

// Function to find the sum of digits
int findSumOfDigits(int num)
{
    int sum = 0;
    while (num > 0) {
        sum += num % 10; // add the last digit to the sum
        num /= 10; // remove the last digit from num
    }
    return sum;
}

// Main driver code
int main(int argc, char* argv[])
{
    int num;

    // Check if at least one command line argument was provided
    if (argc == 1) {
        cout << "No command line arguments found." << endl;
        return 0; // exit program
    }

    // Convert the first command line argument to an integer
    num = atoi(argv[1]);

    // Calculate the sum of digits of the number and output the result
    cout << findSumOfDigits(num) << endl;

    return 0; // exit program
}

Output:

In C:
In Java:
In Python

Time complexity: O(logn)

Auxiliary Space: O(1)

TCS Coding Practice Question | Sum of Digits of a number

Explore