TCS Coding Practice Question | Palindrome String

Given a string, the task is to check if this String is Palindrome or not using Command Line Arguments. Examples:

Input: str = "Geeks"
Output: No

Input: str = "GFG"
Output: Yes

Approach:

Since the string is entered as Command line Argument, there is no need for a dedicated input line
Extract the input string from the command line argument
Traverse through this String character by character using loop, till half the length of the sting
Check if the characters from one end match with the characters from the other end
If any character do not matches, the String is not Palindrome
If all character matches, the String is a Palindrome

Program:

// C program to check if a string is Palindrome
// using command line arguments

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

// Function to reverse a string
int isPalindrome(char* str)
{
    int n = strlen(str);
    int i;

    // Check if the characters from one end
    // match with the characters
    // from the other end
    for (i = 0; i < n / 2; i++)
        if (str[i] != str[n - i - 1])

            // Since characters do not match
            // return 0 which resembles false
            return 0;

    // Since all characters match
    // return 1 which resembles true
    return 1;
}

// Driver code
int main(int argc, char* argv[])
{

    int res = 0;

    // Check if the length of args array is 1
    if (argc == 1)
        printf("No command line arguments found.\n");

    else {

        // Get the command line argument
        // and check if it is Palindrome
        res = isPalindrome(argv[1]);

        // Check if res is 0 or 1
        if (res == 0)
            // Print No
            printf("No\n");
        else
            // Print Yes
            printf("Yes\n");
    }
    return 0;
}

Java

// Java program to check if a string is Palindrome
// using command line arguments

class GFG {

    // Function to reverse a string
    public static int isPalindrome(String str)
    {
        int n = str.length();

        // Check if the characters from one end
        // match with the characters
        // from the other end
        for (int i = 0; i < n / 2; i++)
            if (str.charAt(i) != str.charAt(n - i - 1))

                // Since characters do not match
                // return 0 which resembles false
                return 0;

        // Since all characters match
        // return 1 which resembles true
        return 1;
    }

    // Driver code
    public static void main(String[] args)
    {

        // Check if length of args array is
        // greater than 0
        if (args.length > 0) {

            // Get the command line argument
            // and check if it is Palindrome
            int res = isPalindrome(args[0]);

            // Check if res is 0 or 1
            if (res == 0)
                // Print No
                System.out.println("No\n");
            else
                // Print Yes
                System.out.println("Yes\n");
        }
        else
            System.out.println("No command line "
                               + "arguments found.");
    }
}

Output:

In C:
In Java:

TCS Coding Practice Question | Palindrome String

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