TCS Coding Practice Question | Checking Leap Year

Given a number N, the task is to check if N is a Leap Year or not, using Command Line Arguments. Examples:

Input: N = 2000
Output: Yes
Input: N = 1997
Output: No

Approach:

Since the number is entered as Command line Argument, there is no need for a dedicated input line
Extract the input number from the command line argument
This extracted number will be in string type.
Convert this number into integer type and store it in a variable, say N
Now check for the below conditions:
- if N is a multiple of 400 and
- if N is multiple of 4 and not multiple of 100

Program:

// C program to check if N is a leap year
// using command line arguments

#include <stdio.h>

#include <stdlib.h> /* atoi */

// Function to check
// if year is a leap year or not
int isLeapYear(int year)
{

    // Return 1 if year is a multiple
    // 0f 4 and not multiple of 100.
    // OR year is multiple of 400.
    if (((year % 4 == 0)
         && (year % 100 != 0))
        || (year % 400 == 0))
        return 1;
    else
        return 0;
}

// Driver code
int main(int argc, char* argv[])
{

    int n;

    // Check if the length of args array is 1
    if (argc == 1)
        printf("No command line arguments found.\n");
    else {

        // Get the command line argument and
        // Convert it from string type to integer type
        // using function "atoi( argument)"
        n = atoi(argv[1]);

        // Check if n is a leap year
        if (isLeapYear(n) == 1)
            printf("Yes\n");
        else
            printf("No\n");
    }

    return 0;
}

Java

// Java program to check if N is a leap year
// using command line arguments

class GFG {

    // Function to check
    // if year is a leap year or not
    public static int isLeapYear(int year)
    {

        // Return 1 if year is a multiple
        // 0f 4 and not multiple of 100.
        // OR year is multiple of 400.
        if (((year % 4 == 0)
             && (year % 100 != 0))
            || (year % 400 == 0))
            return 1;
        else
            return 0;
    }

    // Driver code
    public static void main(String[] args)
    {

        // Check if length of args array is
        // greater than 0
        if (args.length > 0) {

            // Get the command line argument and
            // Convert it from string type to integer type
            int n = Integer.parseInt(args[0]);

            // Check if n is a leap year
            if (isLeapYear(n) == 1)
                System.out.println("Yes");
            else
                System.out.println("No");
        }
        else
            System.out.println("No command line "
                               + "arguments found.");
    }
}

Python3

#  Python program to check if N is a leap year
#  using command line arguments

class GFG:
    # Function to check
    # if year is a leap year or not
    @staticmethod
    def isLeapYear(year):
        if ((year % 4 == 0 and year % 100 != 0) or year % 400 == 0):
            return 1
        else:
            return 0

if __name__ == "__main__":
        import sys
       
        # Check if length of args array is
        # greater than 1
        if len(sys.argv) > 1:
        
            # Get the command line argument and
        # Convert it from string type to integer type
            n = int(sys.argv[1])
           
            # Check if n is a leap year
            if GFG.isLeapYear(n) == 1:
                print("Yes")
            else:
                print("No")
        else:
            print("No command line arguments found\nUse : python3 GFG.py <number>")

 #puligokulakishorereddy

Output:

In C:
In Java:
In Python

leap

Time Complexity: O(1)
Auxiliary Space: O(1)

TCS Coding Practice Question | Checking Leap Year

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