Program to print first 10 perfect squares

Write a program to print the first 10 perfect squares. A perfect square is an integer which is the square of some other integer, or we can say that it is a second exponent of an integer.

Output format:

1 4 9 16 25 ....

Approach:

We know that the first 10 perfect squares will be square of 1, square of 2, square of 3... till square of 10. So, iterate from 1 to 10 and print squares of each number.

Step-by-step algorithm:

Run a loop for i = 1 to 10:
- For each iteration, calculate sq = i * i
- Print the square as sq.
After 10 iterations, we will have the first 10 perfect squares.

Below is the implementation of the above approach:

C++

#include <iostream>
using namespace std;

int main() {
    
    for(int i = 1; i <= 10; i++) {
        int sq = i * i;
        cout << sq << " ";
    }
    return 0;
}

Java

/*package whatever //do not write package name here */
public class Main {
    public static void main(String[] args) {
        for (int i = 1; i <= 10; i++) {
            int sq = i * i;
            System.out.print(sq + " ");
        }
    }
}

Python3

# code by flutterfly
for i in range(1, 11):
    sq = i * i
    print(sq, end=" ")

//code by flutterfly
using System;

class Program {
    static void Main() {
        for (int i = 1; i <= 10; i++) {
            int sq = i * i;
            Console.Write(sq + " ");
        }
    }
}

JavaScript

//code by flutterfly
for (let i = 1; i <= 10; i++) {
    let sq = i * i;
    process.stdout.write(sq + " ");
}

Output

1 4 9 16 25 36 49 64 81 100

Time Complexity: O(1)
Auxiliary Space: O(1)

Program to print first 10 perfect squares

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