Given the dimensions of a rectangle (length and breadth), write a program to determine whether the given rectangle is a square or not.
Examples:
Input: Length = 5, Breadth = 5
Output: Square
Explanation: Since the length and breadth of the rectangle is same, therefore the given rectangle is a square.Input: Length = 6, Breadth = 8
Output: Rectangle
Explanation: Since the length and breadth are different, therefore it is a rectangle.
Approach: To solve the problem, follow the below idea:
If the length and breadth of a rectangle are equal, it is a square. Otherwise, it is a rectangle.
Step-by-step algorithm:
- Take the input for length and breadth.
- Check if length equals breadth.
- If true, print "Square." Otherwise, print "Not a Square."
Below is the implementation of the algorithm:
#include <iostream>
using namespace std;
int main() {
int length, breadth;
// Example test case
length = 5;
breadth = 5;
if (length == breadth)
cout << "Square" << endl;
else
cout << "Not a Square" << endl;
return 0;
}
#include <stdio.h>
int main() {
int length, breadth;
// Example test case
length = 5;
breadth = 5;
if (length == breadth)
printf("Square.\n");
else
printf("Not a Square.\n");
return 0;
}
public class SquareChecker {
public static void main(String[] args) {
// Example test case
int length = 5;
int breadth = 5;
if (length == breadth)
System.out.println("Square.");
else
System.out.println("Not a Square.");
}
}
# Example test case
length, breadth = 5, 5
if length == breadth:
print("Square.")
else:
print("Not a Square.")
using System;
class Program {
static void Main() {
// Example test case
int length = 5;
int breadth = 5;
if (length == breadth)
Console.WriteLine("Square.");
else
Console.WriteLine("Not a Square.");
}
}
// Example test case
let length = 5;
let breadth = 5;
if (length === breadth)
console.log("Square.");
else
console.log("Not a Square.");
Output
Square
Time Complexity: O(1)
Auxiliary Space: O(1)