Given a number n, find out the number of Reflexive Relation on a set of first n natural numbers {1, 2, ..n}.
Examples :
Input: n = 2
Output: 4
The given set A = {1, 2}. The following are reflexive relations on A * A :
{{1, 1), (2, 2)}
{(1, 1), (2, 2), (1, 2)}
{(1, 1), (2, 2), (1, 2), (2, 1)}
{(1, 1), (2, 2), (2, 1)}Input: n = 3
Output: 64
Explanation :
Reflexive Relation: A Relation R on A a set A is said to be Reflexive if xRx for every element of x ? A.
The number of reflexive relations on an n-element set is 2n(n-1)
How does this formula work?
A relation R is reflexive if the matrix diagonal elements are 1.
If we take a closer look the matrix, we can notice that the size of matrix is n2. The n diagonal entries are fixed. For remaining n2 - n entries, we have choice to either fill 0 or 1. So there are total 2n(n-1) ways of filling the matrix.
Below is the code implementation of the above approach:
// C++ Program to count reflexive relations
// on a set of first n natural numbers.
#include <iostream>
using namespace std;
int countReflexive(int n)
{
// Return 2^(n*n - n)
return (1 << (n*n - n));
}
int main()
{
int n = 3;
cout << countReflexive(n);
return 0;
}
// Java Program to count reflexive
// relations on a set of first n
// natural numbers.
import java.io.*;
import java.util.*;
class GFG {
static int countReflexive(int n)
{
// Return 2^(n*n - n)
return (1 << (n*n - n));
}
// Driver function
public static void main (String[] args) {
int n = 3;
System.out.println(countReflexive(n));
}
}
// This code is contributed by Gitanjali.
# Python3 Program to count
# reflexive relations
# on a set of first n
# natural numbers.
def countReflexive(n):
# Return 2^(n*n - n)
return (1 << (n*n - n));
# driver function
n = 3
ans = countReflexive(n);
print (ans)
# This code is contributed by saloni1297
// C# Program to count reflexive
// relations on a set of first n
// natural numbers.
using System;
class GFG {
static int countReflexive(int n)
{
// Return 2^(n*n - n)
return (1 << (n*n - n));
}
// Driver function
public static void Main () {
int n = 3;
Console.WriteLine(countReflexive(n));
}
}
// This code is contributed by vt_m.
<?php
// PHP Program to count
// reflexive relations on a
// set of first n natural numbers.
function countReflexive($n)
{
// Return 2^(n * n - n)
return (1 << ($n * $n - $n));
}
//Driver code
$n = 3;
echo countReflexive($n);
// This code is contributed by mits
?>
<script>
// Javascript Program to count reflexive
// relations on a set of first n
// natural numbers.
function countReflexive(n)
{
// Return 2^(n*n - n)
return (1 << (n*n - n));
}
let n = 3;
document.write(countReflexive(n));
// This code is contributed by divyesh072019.
</script>
Output
64
Time Complexity: O(1)
Auxiliary Space: O(1)
