Given a binary grid of order r * c and an initial position. The task is to find the minimum distance from the source to get to the any corner of the grid. A move can be made to a cell grid[i][j] only if grid[i][j] = 0 and only left, right, up and down movements are permitted. If no valid path exists then print -1.
Examples:
Input: i = 1, j = 1, grid[][] = {{0, 0, 1}, {0, 0, 0}, {1, 1, 1}}
Output: 2
(1, 1) -> (1, 0) -> (0, 0)
Input: i = 0, j = 0, grid[][] = {{0, 1}, {1, 1}}
Output: 0
Source is already a corner of the grid.
Approach:
- If source is already any of the corner then print 0.
- Start traversing the grid starting with source using BFS as :
- Insert cell position in queue.
- Pop element from queue and mark it visited.
- For each valid move adjacent to popped one, insert the cell position into queue.
- On each move, update the minimum distance of the cell from initial position.
- After the completion of the BFS, find the minimum distance from source to every corner.
- Print the minimum among these in the end.
Below is the implementation of the above approach:
// C++ implementation of the approach
#include <bits/stdc++.h>
using namespace std;
#define row 5
#define col 5
// Global variables for grid, minDistance and visited array
int minDistance[row + 1][col + 1], visited[row + 1][col + 1];
// Queue for BFS
queue<pair<int, int> > que;
// Function to find whether the move is valid or not
bool isValid(int grid[][col], int i, int j)
{
if (i < 0 || j < 0
|| j >= col || i >= row
|| grid[i][j] || visited[i][j])
return false;
return true;
}
// Function to return the minimum distance
// from source to the end of the grid
int minDistance(int grid[][col],
int sourceRow, int sourceCol)
{
// If source is one of the destinations
if ((sourceCol == 0 && sourceRow == 0)
|| (sourceCol == col - 1 && sourceRow == 0)
|| (sourceCol == 0 && sourceRow == row - 1)
|| (sourceCol == col - 1 && sourceRow == row - 1))
return 0;
// Set minimum value
int minFromSource = row * col;
// Precalculate minDistance of each grid with R * C
for (int i = 0; i < row; i++)
for (int j = 0; j < col; j++)
minDistance[i][j] = row * col;
// Insert source position in queue
que.push(make_pair(sourceRow, sourceCol));
// Update minimum distance to visit source
minDistance[sourceRow][sourceCol] = 0;
// Set source to visited
visited[sourceRow][sourceCol] = 1;
// BFS approach for calculating the minDistance
// of each cell from source
while (!que.empty()) {
// Iterate over all four cells adjacent
// to current cell
pair<int, int> cell = que.front();
// Initialize position of current cell
int cellRow = cell.first;
int cellCol = cell.second;
// Cell below the current cell
if (isValid(grid, cellRow + 1, cellCol)) {
// Push new cell to the queue
que.push(make_pair(cellRow + 1, cellCol));
// Update one of its neighbor's distance
minDistance[cellRow + 1][cellCol]
= min(minDistance[cellRow + 1][cellCol],
minDistance[cellRow][cellCol] + 1);
visited[cellRow + 1][cellCol] = 1;
}
// Above the current cell
if (isValid(grid, cellRow - 1, cellCol)) {
que.push(make_pair(cellRow - 1, cellCol));
minDistance[cellRow - 1][cellCol]
= min(minDistance[cellRow - 1][cellCol],
minDistance[cellRow][cellCol] + 1);
visited[cellRow - 1][cellCol] = 1;
}
// Right cell
if (isValid(grid, cellRow, cellCol + 1)) {
que.push(make_pair(cellRow, cellCol + 1));
minDistance[cellRow][cellCol + 1]
= min(minDistance[cellRow][cellCol + 1],
minDistance[cellRow][cellCol] + 1);
visited[cellRow][cellCol + 1] = 1;
}
// Left cell
if (isValid(grid, cellRow, cellCol - 1)) {
que.push(make_pair(cellRow, cellCol - 1));
minDistance[cellRow][cellCol - 1]
= min(minDistance[cellRow][cellCol - 1],
minDistance[cellRow][cellCol] + 1);
visited[cellRow][cellCol - 1] = 1;
}
// Pop the visited cell
que.pop();
}
int i;
// Minimum distance to the corner
// of the first row, first column
minFromSource = min(minFromSource,
minDistance[0][0]);
// Minimum distance to the corner
// of the last row, first column
minFromSource = min(minFromSource,
minDistance[row - 1][0]);
// Minimum distance to the corner
// of the last row, last column
minFromSource = min(minFromSource,
minDistance[row - 1][col - 1]);
// Minimum distance to the corner
// of the first row, last column
minFromSource = min(minFromSource,
minDistance[0][col - 1]);
// If no path exists
if (minFromSource == row * col)
return -1;
// Return the minimum distance
return minFromSource;
}
// Driver code
int main()
{
int sourceRow = 3, sourceCol = 3;
int grid[row][col] = { 1, 1, 1, 0, 0,
0, 0, 1, 0, 1,
0, 0, 1, 0, 1,
1, 0, 0, 0, 1,
1, 1, 0, 1, 0 };
cout << minDistance(grid, sourceRow, sourceCol);
return 0;
}
// Java implementation of the approach
import java.util.*;
class GFG
{
// Pair class
static class Pair
{
int first,second;
Pair(int a, int b)
{
first = a;
second = b;
}
}
static int row = 5;
static int col = 5;
// Global variables for grid, minDistance and visited array
static int minDistance[][] =
new int[row + 1][col + 1],
visited[][] = new int[row + 1][col + 1];
// Queue for BFS
static Queue<Pair > que = new LinkedList<>();
// Function to find whether the move is valid or not
static boolean isValid(int grid[][], int i, int j)
{
if (i < 0 || j < 0
|| j >= col || i >= row
|| grid[i][j] != 0 || visited[i][j] != 0)
return false;
return true;
}
// Function to return the minimum distance
// from source to the end of the grid
static int minDistance(int grid[][],
int sourceRow, int sourceCol)
{
// If source is one of the destinations
if ((sourceCol == 0 && sourceRow == 0)
|| (sourceCol == col - 1 && sourceRow == 0)
|| (sourceCol == 0 && sourceRow == row - 1)
|| (sourceCol == col - 1 && sourceRow == row - 1))
return 0;
// Set minimum value
int minFromSource = row * col;
// Precalculate minDistance of each grid with R * C
for (int i = 0; i < row; i++)
for (int j = 0; j < col; j++)
minDistance[i][j] = row * col;
// Insert source position in queue
que.add(new Pair(sourceRow, sourceCol));
// Update minimum distance to visit source
minDistance[sourceRow][sourceCol] = 0;
// Set source to visited
visited[sourceRow][sourceCol] = 1;
// BFS approach for calculating the minDistance
// of each cell from source
while (que.size() > 0)
{
// Iterate over all four cells adjacent
// to current cell
Pair cell = que.peek();
// Initialize position of current cell
int cellRow = cell.first;
int cellCol = cell.second;
// Cell below the current cell
if (isValid(grid, cellRow + 1, cellCol))
{
// add new cell to the queue
que.add(new Pair(cellRow + 1, cellCol));
// Update one of its neighbor's distance
minDistance[cellRow + 1][cellCol]
= Math.min(minDistance[cellRow + 1][cellCol],
minDistance[cellRow][cellCol] + 1);
visited[cellRow + 1][cellCol] = 1;
}
// Above the current cell
if (isValid(grid, cellRow - 1, cellCol))
{
que.add(new Pair(cellRow - 1, cellCol));
minDistance[cellRow - 1][cellCol]
= Math.min(minDistance[cellRow - 1][cellCol],
minDistance[cellRow][cellCol] + 1);
visited[cellRow - 1][cellCol] = 1;
}
// Right cell
if (isValid(grid, cellRow, cellCol + 1))
{
que.add(new Pair(cellRow, cellCol + 1));
minDistance[cellRow][cellCol + 1]
= Math.min(minDistance[cellRow][cellCol + 1],
minDistance[cellRow][cellCol] + 1);
visited[cellRow][cellCol + 1] = 1;
}
// Left cell
if (isValid(grid, cellRow, cellCol - 1))
{
que.add(new Pair(cellRow, cellCol - 1));
minDistance[cellRow][cellCol - 1]
= Math.min(minDistance[cellRow][cellCol - 1],
minDistance[cellRow][cellCol] + 1);
visited[cellRow][cellCol - 1] = 1;
}
// remove the visited cell
que.remove();
}
int i;
// Minimum distance to the corner
// of the first row, first column
minFromSource = Math.min(minFromSource,
minDistance[0][0]);
// Minimum distance to the corner
// of the last row, first column
minFromSource = Math.min(minFromSource,
minDistance[row - 1][0]);
// Minimum distance to the corner
// of the last row, last column
minFromSource = Math.min(minFromSource,
minDistance[row - 1][col - 1]);
// Minimum distance to the corner
// of the first row, last column
minFromSource = Math.min(minFromSource,
minDistance[0][col - 1]);
// If no path exists
if (minFromSource == row * col)
return -1;
// Return the minimum distance
return minFromSource;
}
// Driver code
public static void main(String args[])
{
int sourceRow = 3, sourceCol = 3;
int grid[][] = { {1, 1, 1, 0, 0},
{0, 0, 1, 0, 1},
{0, 0, 1, 0, 1},
{1, 0, 0, 0, 1},
{1, 1, 0, 1, 0} };
System.out.println(minDistance(grid, sourceRow, sourceCol));
}
}
// This code is contributed by Arnab Kundu
# Python 3 implementation of the approach
row = 5
col = 5
# Global variables for grid, minDistance and visited array
minDistance = [[0 for i in range(col+1)] for j in range(row+1)]
visited = [[0 for i in range(col+1)]for j in range(row+1)]
# Queue for BFS
que = [[0,0]]
# Function to find whether the move is valid or not
def isValid(grid,i,j):
if (i < 0 or j < 0 or j >= col or
i >= row or grid[i][j] or visited[i][j]):
return False
return True
# Function to return the minimum distance
# from source to the end of the grid
def minDistance1(grid,sourceRow,sourceCol):
# If source is one of the destinations
if ((sourceCol == 0 and sourceRow == 0) or
(sourceCol == col - 1 and sourceRow == 0) or
(sourceCol == 0 or sourceRow == row - 1) or
(sourceCol == col - 1 and sourceRow == row - 1)):
return 0
# Set minimum value
minFromSource = row * col
# Precalculate minDistance of each grid with R * C
for i in range(row):
for j in range(col):
minDistance[i][j] = row * col
# Insert source position in queue
que.append([sourceRow, sourceCol])
# Update minimum distance to visit source
minDistance[sourceRow][sourceCol] = 0
# Set source to visited
visited[sourceRow][sourceCol] = 1
# BFS approach for calculating the minDistance
# of each cell from source
while (len(que)!=0):
# Iterate over all four cells adjacent
# to current cell
cell = que[0]
# Initialize position of current cell
cellRow = cell[0]
cellCol = cell[1]
# Cell below the current cell
if (isValid(grid, cellRow + 1, cellCol)):
# Push new cell to the queue
que.append([cellRow + 1, cellCol])
# Update one of its neighbor's distance
minDistance[cellRow + 1][cellCol] = min(minDistance[cellRow + 1][cellCol],
minDistance[cellRow][cellCol] + 1)
visited[cellRow + 1][cellCol] = 1
# Above the current cell
if (isValid(grid, cellRow - 1, cellCol)):
que.append([cellRow - 1, cellCol])
minDistance[cellRow - 1][cellCol] = min(minDistance[cellRow - 1][cellCol],
minDistance[cellRow][cellCol] + 1)
visited[cellRow - 1][cellCol] = 1
# Right cell
if (isValid(grid, cellRow, cellCol + 1)):
que.append([cellRow, cellCol + 1])
minDistance[cellRow][cellCol + 1] = min(minDistance[cellRow][cellCol + 1],
minDistance[cellRow][cellCol] + 1)
visited[cellRow][cellCol + 1] = 1
# Left cell
if (isValid(grid, cellRow, cellCol - 1)):
que.append([cellRow, cellCol - 1])
minDistance[cellRow][cellCol - 1]= min(minDistance[cellRow][cellCol - 1],
minDistance[cellRow][cellCol] + 1)
visited[cellRow][cellCol - 1] = 1
# Pop the visited cell
que.remove(que[0])
# Minimum distance to the corner
# of the first row, first column
minFromSource = min(minFromSource, minDistance[0][0])
# Minimum distance to the corner
# of the last row, first column
minFromSource = min(minFromSource, minDistance[row - 1][0])
# Minimum distance to the corner
# of the last row, last column
minFromSource = min(minFromSource,minDistance[row - 1][col - 1])
# Minimum distance to the corner
# of the first row, last column
minFromSource = min(minFromSource, minDistance[0][col - 1])
# If no path exists
if (minFromSource == row * col):
return -1
# Return the minimum distance
return minFromSource
# Driver code
if __name__ == '__main__':
sourceRow = 3
sourceCol = 3
grid = [[1, 1, 1, 0, 0],
[0, 0, 1, 0, 1],
[0, 0, 1, 0, 1],
[1, 0, 0, 0, 1],
[1, 1, 0, 1, 0]]
print(minDistance1(grid, sourceRow, sourceCol))
# This code is contributed by
# Surendra_Gangwar
// C# implementation of above approach
using System;
using System.Collections;
using System.Collections.Generic;
class GFG {
// Global variables for grid, minDistance and visited
// array
static class Globals {
// global int
public static int row = 5;
public static int col = 5;
// Global variables for grid, minDistance and
// visited array
public static int[, ] minDistance
= new int[row + 1, col + 1];
public static int[, ] visited
= new int[row + 1, col + 1];
// Queue for BFS
public static Queue<KeyValuePair<int, int> > que
= new Queue<KeyValuePair<int, int> >();
}
// Function to find whether the move is valid or not
static bool isValid(int[, ] grid, int i, int j)
{
if (i < 0 || j < 0 || j >= Globals.col
|| i >= Globals.row || grid[i, j] != 0
|| Globals.visited[i, j] != 0)
return false;
return true;
}
// Function to return the minimum distance
// from source to the end of the grid
static int minDistance1(int[, ] grid, int sourceRow,
int sourceCol)
{
// If source is one of the destinations
if ((sourceCol == 0 && sourceRow == 0)
|| (sourceCol == Globals.col - 1
&& sourceRow == 0)
|| (sourceCol == 0
&& sourceRow == Globals.row - 1)
|| (sourceCol == Globals.col - 1
&& sourceRow == Globals.row - 1))
return 0;
// Set minimum value
int minFromSource = Globals.row * Globals.col;
// Precalculate minDistance of each grid with R * C
for (int i = 0; i < Globals.row; i++)
for (int j = 0; j < Globals.col; j++)
Globals.minDistance[i, j]
= Globals.row * Globals.col;
// Insert source position in queue
Globals.que.Enqueue(new KeyValuePair<int, int>(
sourceRow, sourceCol));
// Update minimum distance to visit source
Globals.minDistance[sourceRow, sourceCol] = 0;
// Set source to visited
Globals.visited[sourceRow, sourceCol] = 1;
// BFS approach for calculating the minDistance
// of each cell from source
while (Globals.que.Count > 0) {
// Iterate over all four cells adjacent
// to current cell
KeyValuePair<int, int> cell
= Globals.que.Dequeue();
// Initialize position of current cell
int cellRow = cell.Key;
int cellCol = cell.Value;
// Cell below the current cell
if (isValid(grid, cellRow + 1, cellCol)) {
// Push new cell to the queue
Globals.que.Enqueue(
new KeyValuePair<int, int>(cellRow + 1,
cellCol));
// Update one of its neighbor's distance
Globals.minDistance[cellRow + 1, cellCol]
= Math.Min(
Globals.minDistance[cellRow + 1,
cellCol],
Globals.minDistance[cellRow,
cellCol]
+ 1);
Globals.visited[cellRow + 1, cellCol] = 1;
}
// Above the current cell
if (isValid(grid, cellRow - 1, cellCol)) {
Globals.que.Enqueue(
new KeyValuePair<int, int>(cellRow - 1,
cellCol));
Globals.minDistance[cellRow - 1, cellCol]
= Math.Min(
Globals.minDistance[cellRow - 1,
cellCol],
Globals.minDistance[cellRow,
cellCol]
+ 1);
Globals.visited[cellRow - 1, cellCol] = 1;
}
// Right cell
if (isValid(grid, cellRow, cellCol + 1)) {
Globals.que.Enqueue(
new KeyValuePair<int, int>(
cellRow, cellCol + 1));
Globals.minDistance[cellRow, cellCol + 1]
= Math.Min(
Globals.minDistance[cellRow,
cellCol + 1],
Globals.minDistance[cellRow,
cellCol]
+ 1);
Globals.visited[cellRow, cellCol + 1] = 1;
}
// Left cell
if (isValid(grid, cellRow, cellCol - 1)) {
Globals.que.Enqueue(
new KeyValuePair<int, int>(
cellRow, cellCol - 1));
Globals.minDistance[cellRow, cellCol - 1]
= Math.Min(
Globals.minDistance[cellRow,
cellCol - 1],
Globals.minDistance[cellRow,
cellCol]
+ 1);
Globals.visited[cellRow, cellCol - 1] = 1;
}
}
// Minimum distance to the corner
// of the first row, first column
minFromSource = Math.Min(minFromSource,
Globals.minDistance[0, 0]);
// Minimum distance to the corner
// of the last row, first column
minFromSource = Math.Min(
minFromSource,
Globals.minDistance[Globals.row - 1, 0]);
// Minimum distance to the corner
// of the last row, last column
minFromSource = Math.Min(
minFromSource,
Globals.minDistance[Globals.row - 1,
Globals.col - 1]);
// Minimum distance to the corner
// of the first row, last column
minFromSource = Math.Min(
minFromSource,
Globals.minDistance[0, Globals.col - 1]);
// If no path exists
if (minFromSource == Globals.row * Globals.col)
return -1;
// Return the minimum distance
return minFromSource;
}
// Driver Code
static void Main()
{
int sourceRow = 3, sourceCol = 3;
int[, ] grid = { { 1, 1, 1, 0, 0 },
{ 0, 0, 1, 0, 1 },
{ 0, 0, 1, 0, 1 },
{ 1, 0, 0, 0, 1 },
{ 1, 1, 0, 1, 0 } };
Console.WriteLine(
minDistance1(grid, sourceRow, sourceCol));
}
}
// The code is contributed by Gautam goel (gautamgoel962)
<script>
// Javascript implementation of the approach
// Pair class
class Pair
{
constructor(a, b)
{
this.first = a;
this.second = b;
}
}
let row = 5;
let col = 5;
// Global variables for grid, minDistance and visited array
let minDistance = new Array(row + 1);
let visited = new Array(row + 1);
for(let i = 0; i < row + 1; i++)
{
minDistance[i] = new Array(col+1);
visited[i] = new Array(col+1);
for(let j = 0; j < col + 1; j++)
{
minDistance[i][j] = 0;
visited[i][j] = 0;
}
}
// Queue for BFS
let que = [];
// Function to find whether the move is valid or not
function isValid(grid,i,j)
{
if (i < 0 || j < 0
|| j >= col || i >= row
|| grid[i][j] != 0 || visited[i][j] != 0)
return false;
return true;
}
// Function to return the minimum distance
// from source to the end of the grid
function _minDistance(grid,sourceRow,sourceCol)
{
// If source is one of the destinations
if ((sourceCol == 0 && sourceRow == 0)
|| (sourceCol == col - 1 && sourceRow == 0)
|| (sourceCol == 0 && sourceRow == row - 1)
|| (sourceCol == col - 1 && sourceRow == row - 1))
return 0;
// Set minimum value
let minFromSource = row * col;
// Precalculate minDistance of each grid with R * C
for (let i = 0; i < row; i++)
for (let j = 0; j < col; j++)
minDistance[i][j] = row * col;
// Insert source position in queue
que.push(new Pair(sourceRow, sourceCol));
// Update minimum distance to visit source
minDistance[sourceRow][sourceCol] = 0;
// Set source to visited
visited[sourceRow][sourceCol] = 1;
// BFS approach for calculating the minDistance
// of each cell from source
while (que.length > 0)
{
// Iterate over all four cells adjacent
// to current cell
let cell = que[0];
// Initialize position of current cell
let cellRow = cell.first;
let cellCol = cell.second;
// Cell below the current cell
if (isValid(grid, cellRow + 1, cellCol))
{
// add new cell to the queue
que.push(new Pair(cellRow + 1, cellCol));
// Update one of its neighbor's distance
minDistance[cellRow + 1][cellCol]
= Math.min(minDistance[cellRow + 1][cellCol],
minDistance[cellRow][cellCol] + 1);
visited[cellRow + 1][cellCol] = 1;
}
// Above the current cell
if (isValid(grid, cellRow - 1, cellCol))
{
que.push(new Pair(cellRow - 1, cellCol));
minDistance[cellRow - 1][cellCol]
= Math.min(minDistance[cellRow - 1][cellCol],
minDistance[cellRow][cellCol] + 1);
visited[cellRow - 1][cellCol] = 1;
}
// Right cell
if (isValid(grid, cellRow, cellCol + 1))
{
que.push(new Pair(cellRow, cellCol + 1));
minDistance[cellRow][cellCol + 1]
= Math.min(minDistance[cellRow][cellCol + 1],
minDistance[cellRow][cellCol] + 1);
visited[cellRow][cellCol + 1] = 1;
}
// Left cell
if (isValid(grid, cellRow, cellCol - 1))
{
que.push(new Pair(cellRow, cellCol - 1));
minDistance[cellRow][cellCol - 1]
= Math.min(minDistance[cellRow][cellCol - 1],
minDistance[cellRow][cellCol] + 1);
visited[cellRow][cellCol - 1] = 1;
}
// remove the visited cell
que.shift();
}
let i;
// Minimum distance to the corner
// of the first row, first column
minFromSource = Math.min(minFromSource,
minDistance[0][0]);
// Minimum distance to the corner
// of the last row, first column
minFromSource = Math.min(minFromSource,
minDistance[row - 1][0]);
// Minimum distance to the corner
// of the last row, last column
minFromSource = Math.min(minFromSource,
minDistance[row - 1][col - 1]);
// Minimum distance to the corner
// of the first row, last column
minFromSource = Math.min(minFromSource,
minDistance[0][col - 1]);
// If no path exists
if (minFromSource == row * col)
return -1;
// Return the minimum distance
return minFromSource;
}
// Driver code
let sourceRow = 3, sourceCol = 3;
let grid = [[1, 1, 1, 0, 0],
[0, 0, 1, 0, 1],
[0, 0, 1, 0, 1],
[1, 0, 0, 0, 1],
[1, 1, 0, 1, 0]];
document.write(_minDistance(grid, sourceRow, sourceCol));
// This code is contributed by avanitrachhadiya2155
</script>
Output:
4